3x^2+19x+42=0

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Solution for 3x^2+19x+42=0 equation: 



3x^2+19x+42=0

a = 3; b = 19; c = +42;
Δ = b2-4ac
Δ = 192-4·3·42
Δ = -143
Delta is less than zero, so there is no solution for the equation

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